In fig. if ⎳abc 20° then ⎳aoc is equal to
WebMay 16, 2024 · In figure, if ∠ABC = 20°, then ∠AOC equals (a) 20° (b) 40° (c) 60° (d) 10° circle class-10 1 Answer +2 votes answered May 16, 2024 by RupamBharti (36.7k points) selected May 16, 2024 by VinodeYadav Best answer Answer is (b) 40° ∠ABC = 20° We know that angle subtended by an arc at the center of circle in double the angle subtended at … WebOct 7, 2024 · Answer: If ∠ABC = 20⁰, then ∠AOC = 40⁰ . Step-by-step explanation: Inscribed Angle Theorem states that, "An angle inscribed in a circle at its circumference is equal to …
In fig. if ⎳abc 20° then ⎳aoc is equal to
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WebSolution Given, ∠OAB=30∘ and ∠OCB= 57∘ In ΔAOB, AO = OB [both are the radius of the same circle] ⇒ ∠OBA= ∠BAO=30∘ [angles opposite to equal sides are equal] ⇒ ∠AOB+∠OBA+∠BAO=180∘ [by angle sum property of a triangle] ∴ ∠AOB+30∘+30∘ =180∘ ∴ ∠AOB= 180∘−2(30∘) ∠AOB=180∘−60∘ = 120∘ ........... (i) Now, in ΔOCB, OC = OB [both are … Web∠AOC = 2 × ∠ABC = 2 × 20° = 40° Therefore, ∠AOC = 40° Hence, option B is the correct answer. 5. In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠ CAB is equal …
WebIn figure, if ∠ABC = 20°, then ∠AOC is equal to (a) 20° (b) 40° (c) 60° (d) 10° Thinking Process Use the theorem, that in a circale the angle subtended by an arc at the centre is … WebApr 7, 2024 · $ \Rightarrow 45^\circ + \angle AOC = 180^\circ $ Solving further, $ \Rightarrow \angle AOC = 180^\circ - 45^\circ = 135^\circ $ Therefore, the required value of $\angle AOC = 135^\circ $ Note: A triangle is a 3-sides polygon having 3 sides, 3 angles and 3 vertices. Also, the sum of any two sides of a triangle is always greater than the third side.
WebIn Fig.10.4, if ABC = 20 , then AOC is equal to: A. 20 B. 40 C. 60 D. 10 Answer: Given: ∠ABC = 20° By theorem “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle”, we have: ∠AOC = 2 × ∠ABC = 2 × 20° = 40° ∴ ∠AOC = 40° Question 5. WebAug 19, 2024 · ∠ABC = 20° We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle” According to the …
WebFeb 19, 2024 · Best answer Given: ∠OBD = 50° Here, AB and CD are the diameters of the circles with centre O. ∠DBC = 90° …. (i) [Angle in the semi-circle] Also, ∠DBC = 50° + ∠OBC 90° = 50° + ∠OBC or ∠OBC = 40° Again, By degree measure theorem: ∠AOC = 2 ∠ABC ∠AOC = 2∠OBC = 2 x 40° = 80° ← Prev Question Next Question → Find MCQs & Mock Test JEE …
WebIn Fig. 10.6, if ∠OAB = 40º, then ∠ACB is equal to : a. 50º b. 40º c. 60º d. 70° Solution: In triangle OAB OA = OB ( radius of a circle) ∠OAB = ∠OBA ∠OBA = 40º (angles opposite to equal sides are equal) Using the angle sum property ∠AOB + ∠OBA + ∠BAO = 180º Substituting the values ∠AOB + 40º + 40º = 180º By further calculation ∠AOB + 80º = 180º pennsylvania civil war uniformsWebSolution In the figure, ∠AOB=80o, ∠ABC= 30o ∵ Arc AB subtends ∠AOB at the centre and ∠ACB at the remaining part of the circle. ∴ ∠ACB= 1 2∠AOB = 1 2×80o =40o In ΔOAB, OA= OB ∴ ∠OAB= ∠OBA But, ∠OAB+∠OBA+∠AOB=180o ∴ ∠OAB+∠OBA+80o =180o ⇒ ∠OAB+∠OAB=180o−80o =100o ∴ 2∠OAB= 100o ⇒ ∠OAB= 100o 2 = 50o Similarly, in … to better understand in frenchWebGet Answers to all your Questions. In Fig.10.4, if \angle ABC = 20^ {\circ}, then \angle AOC is equal to: (A) 20^ {\circ} (B) 40^ {\circ} (C) 60^ {\circ} (D) 10^ {\circ} pennsylvania class a licenseWebNov 19, 2024 · In a given figure , O is centre of circle if angle ABC = 20 degree then angle AOC is equal to : (i) 20 degree (ii) 40 degree (iii) 60 degree (iv) 10 degree See answers Advertisement Advertisement aftabansari48 aftabansari48 ... Advertisement svsatardekar73 svsatardekar73 Answer: Step-by-step explanation: GIVEN:ABC=20. So, angle AOC=2×ABC ... pennsylvania class 2a cityWeb∠ABC : (a) is greater than 180° (b) is equal to 180° (c) is less than 180° (d) has no definite value 25. In the figure, if ∠CAB = 40° and AC = BC, then ∠ADB equal to : (a) 40° (b) 60° (c) 80° (d) 100° 26. In the figure, O is the centre of the circle and ∠PQR = 100°. Then the reflex ∠POR is : (a) 280° (b) 200° (c) 260° (d ... to better yourself wordWebGiven: ∠ABC = 20°. By theorem “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle”, we have: ∠AOC = 2 × … to better yourselfWebIn Fig.10.4, if ∠ABC = 20º, then ∠AOC is equal to: a. 20º b. 40º c. 60º d. 10º Solution: We know that Angle at the centre of the circle is twice the angle at the circumference … to be turned or cast back mirror